![]() It can tell us the number of rows and columns in the image, as well as the spatial coordinates for the left, right, top, and bottom edges of the image. Get the spatial coordinates for drawing the outline ![]() I want to be able to call pixelgrid with no arguments and just it find everything it needs automatically.) h_im = findobj(gca, 'type', 'image') Here's a new figure with an image displayed so that I can show how each step works. Draw the outline using two contrasting lines.Construct a single x-vector and a single y-vector that can be used to draw the entire outline. ![]() Get the spatial coordinates for the left, right, top, and bottom of every row and column of image pixels.Here are the basic steps followed by my pixelgrid function on the File Exchange: That way, the outline is guaranteed to always be visible, regardless of the underlying image pixel colors. To solve this problem, I take the approach of drawing two different lines, in the same locations, with different thicknesses and contrasting colors. No matter what color we choose for the pixel outlines, there is always the possibility that some image pixels will be the same or close to that color. That works for the image above, but it won't work in general. Here's some basic code that draws some gray lines on top of the lines. It would be nice to have a subtle but visible outline around each pixel. It's hard to see the individual pixels, and there's a whole row of white pixels at the bottom of the image that have disappeared into the background of the page. imshow(bw, 'InitialMagnification', 'fit') Īnd here's what it looks like when you display it using imshow. Here's the code for making the tiny image (only 4x7) shown above. ![]() But a reader asked me about it recently, so I found the code and finally submitted it. I intended to submit the code to the File Exchange, but I got sidetracked and never did that. Some years ago, I blogged about how to overlay a pixel grid on an image, so that you could clearly see pixel boundaries on a zoomed-in view of the image.
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